Deriving Electric Field Near Metal Plate: Coulomb's & Gauss' Law

AI Thread Summary
The discussion focuses on deriving the electric field near a square metal plate using Coulomb's and Gauss' laws. The expected result for the electric field is E = σ / ε, where σ represents charge per unit area and ε is the relative permeability. Participants express confusion over calculations, particularly regarding the integration process and the application of Coulomb's law. There is a suggestion to use Gauss' theorem to simplify the derivation, emphasizing the need for a suitable Gaussian surface. The conversation highlights the challenges in correctly applying these fundamental principles to obtain the desired result.
j-lee00
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What is the field near a square metal plate (with infinitesimal thickness)

The answer is E = \sigma / \epsilon

where \sigma = Charge per unit area

\epsilon = relative permeabily

Please help me to derive this result. using coulombs and then gauss' law
 
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What will be the first step?
 
For coulomb

\int dE = k \sigma\int 1/r^2 dA

Im getting

E = \sigma \pi / 8 \epsilon

The symbolys are multiplying not tothe power of. This result is wrong
 
I didn't understand how did u get that answer.
newayz, try using gauss theorem... what is the Gaussian surface here?
 
no i want to use colomb
 
K, then you have take a disc with infinitesimal width, find electric field due to it, and integrate for radius = 0 to infinity(coz the sheet is infinite)
 
i know
 
im just not getting the right ans
 
k, tell me what is electric field at a distance x from the infinitesimally wide disc of radius r ?
 
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