Deriving Mechanics Equations for the Moon

AI Thread Summary
The discussion focuses on deriving equations related to a moon's elliptical orbit around a planet. The user successfully derived the orbital radius at periapse and apoapse as r=a(1-e) and r=a(1+e), respectively. They also calculated the ratio of the moon's speed at periapse and apoapse, resulting in vp/va=(1+e)/(1-e). Confusion arose regarding the total energy equation at apoapse and periapse, specifically in combining gravitational potential and kinetic energy. Ultimately, the user resolved their confusion and found the correct approach to the problem.
Dime
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Alright, so I have a few questions.
a) Consider a moon of mass m orbiting a planet of mass M in an elliptical orbit. The equation for the radius of an elliptical orbit is r=a(1-e2) / (1+ecos\vartheta). Derive equations for the orbital radius of the moon when it closest to and farthest from the planet.
My answer turns out to be periapse: r=a(1-e)
and for apoapse: r=a(1+e) a is the semi major axis of the ellipse and e is the eccentricity

b) Combing your result from a with angular momentum (L=mvr), derive an equations for the ratio of the moon's speed at periapse and apoapse in terms of eccentricty, that is vp/va.
I ended up getting vp/va=(1+e) / (1-e)​

c) Write down the equation which equates the total energy of the moon at apoapse with its total energy at periapse using the equation Ep=-GMm / r
I am getting confused with this one. So the total energy would be the gravitational potential energy plus the kinetic energy right? So for the energy at periapse would look like
E=(-GMm / r) + 1/2mv2
the velocity being the one derived earlier.
then using the equations derived in the first couple parts I end up getting
E=(-2GMm + mv(1-e)) / (2a(1-e)​
And somehow I think that is wrong. The next part asks me to show that at periapse
v2=(GM / a)[(1+e)/(1-e)]​
but I may be over complicating things for part c and trying to solve d at the same time I am not sure. Anyone have any ideas if I made a mistake earlier or if they can offer some advice in solving it?
 
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nevermind I figured it out
 
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