Designing a Couette Cell - Get the Right Shear Gradient

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The discussion centers on the design of a Couette cell, specifically involving two concentric cylinders where the inner one rotates and the outer one remains static. The user presents two scenarios with different cylinder diameters and their corresponding RPMs to achieve a shear gradient of 3000/sec. The first scenario, with diameters of 28.64789 mm and 29.64789 mm, is noted to be incorrect, while the second scenario with diameters of 10.0 mm and 11.0 mm is confirmed as correct. The user seeks validation of their understanding of the Couette cell design. Overall, the focus is on achieving accurate shear gradients through proper cylinder specifications.
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I believe I have an understanding of the proper design for a Couette cell. If I am incorrect, please let me know.

Two concentric cylinders, the internal one rotating, the external one static.

1.) If I have a rotating cylinder with a diameter of 28.64789 mm and a static one with a diameter of 29.64789 mm, then 1000 RPM will produce a shear gradient = 3000/sec

2.) If I have a rotating cylinder with a diameter of 10.0 mm and a static one with a diameter of 11.0 mm, then 2864.789 RPM will produce a shear gradient = 3000/sec

Thank you in advance.
 
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J4MacDonald said:
I believe I have an understanding of the proper design for a Couette cell. If I am incorrect, please let me know.

Two concentric cylinders, the internal one rotating, the external one static.

1.) If I have a rotating cylinder with a diameter of 28.64789 mm and a static one with a diameter of 29.64789 mm, then 1000 RPM will produce a shear gradient = 3000/sec

2.) If I have a rotating cylinder with a diameter of 10.0 mm and a static one with a diameter of 11.0 mm, then 2864.789 RPM will produce a shear gradient = 3000/sec

Thank you in advance.
The first answer should be about 1000/sec. The 2nd answer is correct.
 
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