Determine the x-coordinate of the mass center of the homogeneous hemisphere

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Homework Help Overview

The problem involves determining the x-coordinate of the mass center of a homogeneous hemisphere from which a smaller hemispherical portion has been removed. The context is rooted in concepts of center of mass and integration in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to set up an integral to find the center of mass but arrives at an incorrect result. They express uncertainty about the integration limits and the method used, specifically questioning the necessity of a triple integral.

Discussion Status

Participants are actively engaging with the original poster's approach, questioning the setup of the integral and suggesting that a more comprehensive integration method may be needed. There is a focus on clarifying the mathematical representation of the problem.

Contextual Notes

There is mention of the need to consider the removal of the smaller hemisphere and the implications this has on the integration process. The original poster's integration limits and the dimensionality of the integral are under scrutiny.

Godblessyou
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Homework Statement


Determine the x-coordinate of the mass center of the homogeneous hemisphere with the smaller hemispherical portion removed?

I know what the answer should be it's Xcm = 45/112 R

Homework Equations



The center of mass R of a system of particles is defined as the average of their positions, ri, weighted by their masses, mi


The Attempt at a Solution


dm = pi*p*(R^2 - x^2)
and then doing the (integral of x*(dm/dx)*dx)/integral from 0 to R (dm/dx)*dx
which finally gives me 3/2R but this is wrong. Please someone help thanks
 

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Godblessyou said:

Homework Statement


Determine the x-coordinate of the mass center of the homogeneous hemisphere with the smaller hemispherical portion removed?

I know what the answer should be it's Xcm = 45/112 R

Homework Equations



The center of mass R of a system of particles is defined as the average of their positions, ri, weighted by their masses, mi


The Attempt at a Solution


dm = pi*p*(R^2 - x^2)
and then doing the (integral of x*(dm/dx)*dx)/integral from 0 to R (dm/dx)*dx
which finally gives me 3/2R but this is wrong. Please someone help thanks

It's a little hard to tell without the integral in Latex notation, but did you remember to remove the smaller hemisphere? Why is your integration from 0 to R? And why isn't it a triple integral?
 
Yes I did remove smaller hemisphere from bigger which gave me 3/2R. I don't understand what you mean and what you are asking?
 
Godblessyou said:
Yes I did remove smaller hemisphere from bigger which gave me 3/2R. I don't understand what you mean and what you are asking?

I mentioned Latex to help you post your equations in a format that is more readable. Look at the Latex Tutorial thread in the Learning Materials area of the PF:

https://www.physicsforums.com/forumdisplay.php?f=151

I mentioned the triple integral, because what you wrote looks like a 1-D integration, and it would seem that you need to integrate over the volume of the object, no?
 

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