Determining Normal Forces for Particle P

AI Thread Summary
Particle P, with a mass of 1 kg and an upward acceleration of 2.46 m/s², requires the determination of the normal forces exerted by the rod and slot. The normal force from the slot, Nslot, is calculated as 9.8 N, directed horizontally. The normal force from the rod, Nrod, is initially miscalculated but is later corrected to account for the weight of the particle, leading to a revised understanding of its direction and magnitude. The discussion emphasizes the importance of considering all forces acting on the particle, including gravitational force. The final insights suggest that the calculations were refined through collaborative problem-solving.
songoku
Messages
2,470
Reaction score
383

Homework Statement


Particle P has a mass of 1 kg and is confined to move along the smooth vertical slot due to the rotation of the arm AB. Assume that at the instant as shown, the acceleration of particle P is 2.46 ms-2 upward. Determine the normal force Nrod on the particle by the rod and the normal force Nslot on the particle by the slot in the position shown. Friction forces are negligible.

slot.jpg



Homework Equations


F = ma



The Attempt at a Solution


I think that the Nslot is directed out of the page and equals to W so Nslot = 1*9.8 = 9.8 N

Then, Nrod is directed to the top left and is perpendicular to AB. So, Nrod can be projected to Nrod cos 30o directed vertically. Hence :
Nrod cos 30o = m*a
Nrod = 2.84 N

But there is no such answer in the multiple choices...

Thanks
 
Physics news on Phys.org
Nslot is normal to the walls of the slot, so it is in-plane and horizontal. As for Nrod, you are right, Nrod is perpendicular to AB, but there is the weight of the body which is vertical and points downward.

ehild
 
Hi ehild

Ok I think that Nslot is the projection of the normal force in horizontal direction and yes I forgot to take the weight into account. I think I figure out the answer

Thanks a lot !
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
I was thinking using 2 purple mattress samples, and taping them together, I do want other ideas though, the main guidelines are; Must have a volume LESS than 1600 cubic centimeters, and CAN'T exceed 25 cm in ANY direction. Must be LESS than 1 kg. NO parachutes. NO glue or Tape can touch the egg. MUST be able to take egg out in less than 1 minute. Grade A large eggs will be used.
Back
Top