Determining Number of Electrons moving through a lamp.

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To determine the number of electrons moving through a neon indicator lamp, one must first understand the relationship between current, charge, and time. The lamp operates at 90 volts and draws a current of 0.5 mA, which translates to 0.0005 A. Using the formula for current, I = ΔQ/Δt, where ΔQ is the charge and Δt is time, we can calculate the charge that flows in one second as ΔQ = I * Δt, resulting in 0.0005 coulombs. Given that the charge of one electron is approximately 1.6 x 10^-19 coulombs, the total number of electrons passing through the lamp in one second can be calculated by dividing the total charge by the charge of a single electron. This approach provides a clear method for calculating electron flow in electrical circuits.
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The question I'm having trouble is:

A neon indicator lamp needs 90v to conduct. It then draws out 0.5mA.
Calculate the number of electrons moving through the lamp each second.

so...
Electron Charge - 1.6*10^-19
Voltage - 90
Current - 0.5mA​

Any sort of help would be helpful!
 
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What are the units on the electron charge Number?

What is the definition of current?

We need you do show some effort before more help can be given.
 
Recall, 1 electron has charge e=1.6×10^{-19} C, this means that 100 electrons would have charge 100e, etc. Current I is a measure of the change in charge per change in time. I=\frac{ΔQ}{Δt}. You can think of current as a flow of electrons, and the current is a measure of how many electrons pass a fixed point per some time interval.

You know the current already as 0.0005 A, so you should be able to find the amount of charge after 1 second by setting Δt=1s and solving for ΔQ in the above equation. ΔQ, like I said can be thought of as an amount of electrons that passed some fixed point in 1 second.

Now ask yourself how many electrons do I have after 1 second, according to ΔQ?

It's a simple ratio between how many electrons are in 1e, and how many electrons are in your ΔQ. It should look like this:

\frac{1.6×10^{-19}C}{1e}=\frac{ΔQ}{Ne}. where N is the number of electrons that passed through the wire in 1 second.
 
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