Determining pressure at equilibrium with Kp

AI Thread Summary
To determine the equilibrium pressure of O2 in the reaction 4 Fe3O4(s) + O2(g) <----> 6 Fe2O3(s) with Kp = 2.5 x 10^87, the equilibrium constant expression should only include gases. The correct formulation for Kp is Kp = P(Fe2O3)^6 / P(O2), leading to the conclusion that P(O2) must be calculated as 1/(Kp^(1/2)). The user initially miscalculated the pressure, leading to confusion regarding significant digits and the correct application of the equilibrium constant. Clarification on the proper use of Kp and significant figures is essential for accurate calculations.
Emworthington
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Homework Statement


The minerals (Fe2So3) and (Fe3O4) exist in equilibrium with atmospheric oxygen.

4 Fe3O4(s) + O2(g) <----> 6 Fe2O3(s) kp = 2.5 x 10^87

Determine P(O2) at equilibrium

Homework Equations


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The Attempt at a Solution


Since the equilibrium constant can only have gases in it, I assumed that the equation would be
1/[O2]^2 so that the pressure would be 1/2.5*10^87. However, it's an online program and says that that (4*10^-88) is wrong. It also says that 2.5*10^87 is wrong. What else do you think I could do?
 
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No idea why 1/[O2]2 and not just 1/[O2], but perhaps that's just a typo.

Some of these HW programs are very anal about significant digits.
 
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