Different ways that Log appears

  • Thread starter Thread starter grscott_2000
  • Start date Start date
  • Tags Tags
    Log
AI Thread Summary
The discussion clarifies that loge(x) is indeed the same as ln(x), which is the natural logarithm. It emphasizes that e^x is not the same as the natural logarithm; rather, it is the inverse of ln(x). The notation loge(x) is used to specify the base of the logarithm as e, eliminating confusion with other logarithmic bases. Participants express appreciation for the clarification, indicating that it simplifies their understanding of integration. Overall, the thread effectively resolves confusion regarding logarithmic notation and its implications in integration.
grscott_2000
Messages
48
Reaction score
0
Not so much a question query here but a query about how my question is written.

Im having to do some integration and my question has one part loge (log sub e). I think that this is just natural log which i usually see written as ln(x). Is this correct? However my table of integrals has e^x. Is this the same too? I seem to be getting confused by all the different ways of writting these logrithms. Can someone clarify please as to what each of these terms really means?

Regards
 
Physics news on Phys.org
grscott_2000 said:
Im having to do some integration and my question has one part loge (log sub e). I think that this is just natural log which i usually see written as ln(x). Is this correct?
Correct, loge(x) is identical to ln(x) and is given the name "natural logarithm".
grscott_2000 said:
However my table of integrals has e^x. Is this the same too?
However, ex is not the same as the natural logarithm, it is in fact it's inverse. Explicitly,

\log_e\left(e^x\right) = \ln\left(e^x\right) = x

And,

e^{\ln(x)} = x

Similarly,

\log_a\left(a^x\right) = x

And,

a^{\log_a(x)} = x

I hope this helps clear things up for you.
 
grscott_2000 said:
Not so much a question query here but a query about how my question is written.

Im having to do some integration and my question has one part loge (log sub e). I think that this is just natural log which i usually see written as ln(x). Is this correct?

Hi!

log_e(x) means the same as ln(x).

You would pronounce it "logarithm, base e".

I suspect that the examiner is worried that some people use "log" for natural logs (I prefer that), and some for log-base-10, so he's written "log_e(x)" to remove any doubt. :smile:
However my table of integrals has e^x. Is this the same too?

Sorry, I don't follow this part of your query. :confused:
 
Many thanx... Thats just what I was looking for. Things should be straightforward now, well as straightforward as integration can be i suppose!

Again many thanks for the help
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top