# Differentiation quotient rule question, am i wrong or is my book wrong?

1. Aug 18, 2009

Differentiate with respect to x; (using the quotient rule)
3/2x-1 (3 over 2x minus 1)
dy/dx = (2x-1)(0) - (3)(2) / (2x-1)^2
dy/dx = -6/(2x-1)^2

but my book gives -2/(2x-1)^2

now,
y = u/v and i take
u = 3 and
v = 2x-1.

dy/dx = v(du/dx) - u(dv/dx) / (v)^2

hmm...
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Aug 18, 2009

### Elucidus

Assuming the question is to find

$$\frac{d}{dx} \; \frac{3}{2x-1}$$