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Difficult Introductory Electricity Circuit Problem - Capacitors

  1. May 2, 2014 #1
    Difficult Introductory Electricity Circuit Problem -- Capacitors

    1. The problem statement, all variables and given/known data

    MAvH81u.png

    3. The attempt at a solution

    This problem was very difficult, and the most I could do was re-arrange the circuit into a make-shift Wheatstone bridge with all capacitors instead of resistors/voltmeter.

    Any ideas?
     
    Last edited: May 2, 2014
  2. jcsd
  3. May 2, 2014 #2

    BvU

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    What you need is a relevant equation ! Hence the template...

    I propose Q = C V There are five of them, plus one for the equivalent over-all C, so you should get enough material to solve for the latter.

    That's how we do parallel, series, etc. of two capacitors. This one is a little more involved.
     
  4. May 2, 2014 #3
    I've already attempted doing that - I think the big problem is that since no two of them are in series/parallel with each other, it's very difficult to use the standard method.
     
  5. May 2, 2014 #4

    BvU

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    Show what you did, it might be just right, only a bit confusing
     
  6. May 2, 2014 #5
    I scrapped my approach because it wasn't working.

    Do you mean I should calculate the charge on the capacitors using Q = VC?
     
  7. May 2, 2014 #6

    SammyS

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    Are the capacitances all different, or do all capacitors have the same capacitance?
     

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  8. May 2, 2014 #7
    They're all different...does that make a difference? I figure the calculation would be the same.
     
  9. May 2, 2014 #8

    NascentOxygen

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    The special case of all being equal allows you to make a drastic simplification right from the start, basing this on symmetry of the circuit. For this reason, the special case cannot qualify as a "challenge problem". :smile:
     
  10. May 2, 2014 #9

    berkeman

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    I just write the KCL equations for complicated questions like this.
     
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