- #1

pmd28

- 64

- 0

## Homework Statement

Sound exits a diffraction horn loudspeaker through a rectangular opening like a small doorway. Such a loudspeaker is mounted outside on a pole. In winter, when the temperature is 273 K, the diffraction angle θ has a value of 11°. What is the diffraction angle for the same sound on a summer day when the temperature is 307 K?

## Homework Equations

v=sqrt([itex]\gamma[/itex]kT/m)

v=[itex]\lambda[/itex]f

sin[itex]\theta[/itex]=[itex]\lambda[/itex]/D

## The Attempt at a Solution

I can't seem to relate these equations. I know that [itex]\gamma[/itex]k/m is constant for both T and I also know that v increases with temperature but I don't understand how that affects lambda and frequency.