Diffraction, interference, single and double slit setups

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SUMMARY

The discussion focuses on the calculations involved in diffraction and interference patterns in single and double slit setups. Participants emphasize the importance of correctly applying the sine function, specifically noting that for small angles, the approximation ##\sin{\theta} \approx \theta## is valid. The calculations provided yield angles of approximately 0.30 degrees and 0.36 degrees, highlighting the precision required in these measurements.

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  • Understanding of wave optics principles
  • Familiarity with the sine function and its approximations
  • Basic knowledge of diffraction and interference phenomena
  • Experience with angle measurement in radians and degrees
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Yangi
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Homework Statement
Hey,
due to the corona—virus here in Germany all schools are closed down. Today our teacher gave us two tasks but I'm not sure which formulars I should use.

1.Calculate the Angel below the 3rd.diffraction minimum behind a single slith that's 0.3 mm width. The laserpointer is a red one with a wave length of 630nm.

2.A parallel red light falls through a double slit. Interference appears on a screen that's 3meters away from the lightsource.The distance between the 1st and zero maximum is 4mm. The column spacing d=0,5mm.
Calculate the Wave length of the red light

Thanks in advance
Relevant Equations
I have added a picture with my attempts to find a solution and equations..
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I think you might have forgotten to multiply by 3 on your calculator for the first part. Also make sure to write ##\theta## in the argument of the ##\sin## function in your working! Also note that for small ##\theta##, we have ##\sin{\theta} \approx \theta## so often we can just use ##\theta = \frac{\lambda}{s}## - though in this case it's small enough that the two are the same to pretty high precision!

I agree with your part 2.
 
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Thank your for the fast reply. I corrected the first one now I got 0.30 degree is this right ?
 
Yangi said:
Thank your for the fast reply. I corrected the first one now I got 0.30 degree is this right ?

If you do want to convert it to degrees, I get a value of 0.36 degrees.
 

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