Dihedral angles for expanded icosidodecahedron.

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SUMMARY

The discussion centers on determining the dihedral angles for the expanded icosidodecahedron, specifically the angles between a pentagon and a square, and between a square and a triangle. The polyhedron is constructed by inserting squares between the pentagons and triangles of an icosidodecahedron and incorporating golden rhombi at each vertex. The known dihedral angle between a rhombus and a square is 162°, while the dihedral angle between the pentagons and triangles in the original icosidodecahedron is 142.62°. The original poster successfully resolved their inquiry independently.

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StevenM
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I am trying to determine two dihedral angles for this polyhedron:

http://georgehart.com/virtual-polyhedra/vrml/zonish-6-icosidodecahedron.wrl

1. The angle between a pentagon and a square?
2. The angle between a square and a triangle?

This polyhedron is formed by adding squares between the pentagons and triangles of an icosidodecahedron, and adding golden rhombi where each of the vertices are.

This polyhedron can also be viewed at the top of this page if you do not have the plugin to view the 3D model:

http://www.georgehart.com/virtual-polyhedra/zonish_polyhedra.html

I know that the dihedral angle between a rhombus and a square is 162°, and that in an icosidodecahedron the dihedral angle is 142.62° between the pentagons and triangles before the squares are added. Any help would be appreciated.
 
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Nevermind. I figured it out. :)
 

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