Dimensional analysis and exponents

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Homework Help Overview

The discussion revolves around dimensional analysis in the context of a simple pendulum's period, T, which is expressed in terms of the pendulum's length, L, and the acceleration due to gravity, g. The original poster seeks to determine the powers p and q in the equation T = 2 (pi) Lp gq for dimensional consistency.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the dimensional analysis required to find the powers p and q. There are attempts to manipulate the equation to compare dimensions on both sides, leading to questions about the relationships between the variables involved.

Discussion Status

The discussion is ongoing, with participants exploring the algebraic manipulation of the equation and questioning how to equate dimensions. Some guidance has been offered in the form of hints about the units involved, but no consensus has been reached on the values of p and q.

Contextual Notes

Participants are working under the constraints of a homework assignment without prior explanation from the teacher, which may affect their understanding of the concepts involved.

addedline8
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I decided to take physics this year, my senior year in high school, and my teacher has decided he isn't going to explain things before he assigns us homework. Any and all help is appreciated.

1. The period T of a simple pendulum is the amount of time required for it to undergo one complete oscillation. If the length of the pendulum is L and the acceleration of gravity is g, then T is given by:
2. T = 2 (pi) Lp gq
3. T = 2 (pi) Lp (L/T2)q

Find the powers p and q required for dimensional consistency.
 
Last edited:
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Hint. L is in meters, g is in meter/second^2 and period T is in seconds. Now just do the algebra.
 
addedline8 said:
I decided to take physics this year, my senior year in high school, and my teacher has decided he isn't going to explain things before he assigns us homework. Any and all help is appreciated.

1. The period T of a simple pendulum is the amount of time required for it to undergo one complete oscillation. If the length of the pendulum is L and the acceleration of gravity is g, then T is given by:



2. T = 2 (pi) Lp gq



3. T = 2 (pi) Lp (L/T2)q

Find the powers p and q required for dimensional consistency.

keep going the way you have started..

T = 2 (pi) Lp (L/T2)q

T = 2 (pi) Lp Lq/T2q

T = 2 (pi) Lp+q.T -2q

Now compare dimensions left and right.

What must -2q equal?

What must p+q equal?
 
Thanks a lot guys. I appreciate the help.
 

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