What Should Be the Radius of Curvature of the Other Surface?

AI Thread Summary
The discussion centers on calculating the radius of curvature for a corrective lens with a prescription of +1.50 diopters, using a lens material with a refractive index of 1.46 and a preformed convex front surface radius of 19.0 cm. The equation used is based on the lensmaker's formula, which relates the focal length to the radii of curvature. A participant points out a potential error in unit consistency, noting that the diopter value should correspond to focal length in meters, while the radius is given in centimeters. This discrepancy may lead to incorrect calculations, prompting a need for clarification on unit conversions. Accurate calculations are essential for determining the correct radius of curvature for the lens design.
lostfan176
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Homework Statement



A prescription for a corrective lens calls for +1.50 diopters. The lensmaker grinds the lens from a "blank" with n = 1.46 and a preformed convex front surface of radius of curvature of 19.0 cm. What should be the radius of curvature of the other surface?


Homework Equations



<br /> \frac{1}{f} = (n-1)\left ( \frac{1}{R_1} - \frac{1}{ R_2} \right ) <br />

The Attempt at a Solution



1.5=(1.46 - 1)(1/19 - 1/x)

(1.5/.46) - 1/19 = 3.208
-1/3.208 = -.3117

which is wrong
am i doing this right cause i don't think i am
 
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Hi lostfan176,

One thing I see: the value in diopters of a lens is the inverse of the focal length in meters. When you wrote 1/f=1.5, you chose your units of length in meters, but then you wrote R1 in centimeters.
 
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