Dipole in electric field, capacitor

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SUMMARY

The discussion focuses on calculating the surface charge density of bound charges on a layer of distilled water within a parallel plate capacitor. The dipole moment of a water molecule is given as 6.1 x 10-30 C·m, and the dielectric constant of water is 80. The formula for surface charge density of bound charges is provided as σbounded = σfree [1 - 1/εr]. The participants emphasize the need for a method to incorporate the dipole moment into the solution.

PREREQUISITES
  • Understanding of parallel plate capacitors
  • Knowledge of dipole moments and their significance in electric fields
  • Familiarity with dielectric materials and their properties
  • Basic grasp of electrostatics and surface charge density calculations
NEXT STEPS
  • Research the relationship between dipole moments and electric fields in dielectric materials
  • Learn about the derivation and application of the bound charge density formula
  • Explore the effects of varying dielectric constants on capacitor performance
  • Investigate advanced topics in electrostatics, such as polarization in different materials
USEFUL FOR

This discussion is beneficial for physics students, electrical engineers, and anyone involved in capacitor design or studying dielectric materials in electric fields.

burak_ilhan
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a parallel plate capacitor is filled with a layer of distilled water of 0.3cm tihck. The dipole moment of a water molecule is 6.1*10^(-30) C.M. Assume that the dipole moments of the water molecules are all perfectly aligned with the electric field. What is the surface charge density of bound charges on the surface of the layer of water.(dielectric constant of water:80).

Well, I solved lots of problems like that except with a dipole moment. I don't know where to use that. I tried to use some energy relations but no results. Thanks for any help.
 
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surface charge density \sigma
\sigma _{bounded} = \sigma _{free} [ 1-\frac{1}{\epsilon _{r}}]
 
Thanks but I know that formula, and I bet everybody knows... I need a way to solve the problem.:)
 

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