Discovering the Minimum Value of Tan(x^2+2x) without a Calculator

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Find where the min value will occur of tan(x^2+2x)

is there a way to do this without a calculator because I can't seem to figure it out without it. Also I'm not sure what the interval should be.
 
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Punkyc7 said:
Find where the min value will occur of tan(x^2+2x)

is there a way to do this without a calculator because I can't seem to figure it out without it. Also I'm not sure what the interval should be.

There's always Calculus!

What's the derivative of tan(x2+2x) ?

BTW: There is no absolute minimum.

There is one relative minimum which can be easily found using the derivative.
 
sec^2(x^2+2x)*(2x+2)... I got it now. Thanks, I was messing up my line check.
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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