Discrete probability distributions

somecelxis
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Homework Statement


Here's the question:
Given X is a discrete random variable. E(X-2) = 1/3 , VAR(X-2) = 20/9 .
Detrmine value of E(X^2)
the ans is 23/3 . but i ended up getting 3 . why i am wrong?


Homework Equations





The Attempt at a Solution

 

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somecelxis said:

Homework Statement


Here's the question:
Given X is a discrete random variable. E(X-2) = 1/3 , VAR(X-2) = 20/9 .
Detrmine value of E(X^2)
the ans is 23/3 . but i ended up getting 3 . why i am wrong?


Homework Equations





The Attempt at a Solution


##\text{Var}(X-2) = \text{Var}(X)## because ##\text{Var}(\cdot)## is unaffected by a non-random shift. Also: ##\text{Var}(X) = E(X^2) - (EX)^2##.
 
somecelxis said:

Homework Statement


Here's the question:
Given X is a discrete random variable. E(X-2) = 1/3 , VAR(X-2) = 20/9 .
Detrmine value of E(X^2)
the ans is 23/3 . but i ended up getting 3 . why i am wrong?

You made a mistake when expanding (x-2)2.

ehild
 
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ehild said:
somecelxis said:

Homework Statement


Here's the question:
Given X is a discrete random variable. E(X-2) = 1/3 , VAR(X-2) = 20/9 .
Detrmine value of E(X^2)
the ans is 23/3 . but i ended up getting 3 . why i am wrong?

You made a mistake when expanding (x-2)2.

ehild

I guess I would have caught that if the OP had typed out his work, but since I never read attached thumbnails I missed it.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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