Does a rigid rod store any energy?

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A rigid rod can be modeled as a spring with a spring constant k and compression x, where the potential energy is calculated using the formula E = 1/2 kx^2. When a force F is applied, the relationship F = kx holds, allowing the potential energy to also be expressed as E = 1/2 (F^2/k). As the spring constant k approaches infinity, the energy stored in the spring approaches zero for any applied force. The work done by the applied force during compression also confirms this, as the displacement approaches zero for a very stiff spring. Therefore, a rigid rod does not store energy effectively under these conditions.
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I presume that a rod can be modeled as a spring with spring constant k and compression x.

The potential energy in a spring is given by:
<br /> E = \frac{1}{2}kx^2<br />
If the spring is in equilibrium with an applied force F then we have:
<br /> F = k x<br />
Thus the potential energy in the spring in terms of the force is:
<br /> E = \frac{1}{2}\frac{F^2}{k}<br />
Thus if we have a very stiff spring so that k\rightarrow\infty then the energy stored in the spring tends to zero for any force applied to the spring.

Is that correct?
 
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You answered your own question.

Chet
 
Perhaps confirm it by looking at the work done by the applied force as it compresses the spring?

work = force * displacement

If the spring is very stiff the displacement is going to approach zero.
 
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