Does Point A Oscillate in Simple Harmonic Motion with a Wave?

AI Thread Summary
Point A on a transverse sinusoidal wave oscillates in simple harmonic motion (SHM) with a frequency equal to that of the wave. Each particle of the medium moves transversely in a sinusoidal manner over time, aligning with the wave's frequency. The nature of SHM is defined by sinusoidal oscillation, which is consistent with the wave's behavior. The wave equation demonstrates that any point along the wave exhibits the same sinusoidal variation, albeit with a phase shift. Thus, the conclusion is that the oscillation of point A is indeed SHM, matching the wave's frequency.
smithj1990
Messages
5
Reaction score
0
you have a transverse sinusoidal wave on a string, and say there's a point A on that string.
does point A oscillate in simple harmonic motion with a frequency that's equal to the frequency of the wave?
 
Physics news on Phys.org
That is a good question. What do you think?

(Please review forum guidelines. We are not here to do your homework.)

What are the characteristics of simple harmonic motion?
 
sorry, its not a homework question. I am simply curious if it is true. I am pretty positive the point would be in SHM. i just don't know how to justify that its SHM frequency of the point would be the frequency of the wave..
im not really sure what equation would be useful here.
 
Well it is true. If the wave moves at a continuous speed, and the y-position of the wave follows a sine function of the x-position, then each particle of the medium will need to moved transversely as a sine function of time. Every point on the wave will need to be at maximum amplitude at exactly the moment that the crest of the wave passes by that point, for every cycle. Therefore, both must have the same frequency.

Since the nature of SHM is sinusoidal, by definition any back-and-forth oscillation that is sinusoidal with time will be SHM.
 
If the transverse wave is moving assuming it's not a standing wave - wouldn't really matter if it was, all that happens is that the amplitude is now a function of x - the wave obeys:
y = A*sin(wt \pm kx)

Choosing the origin, it doesn't matter where you look along the wave, the wave equation is now:
y = A*sin(wt)

In other words, a sinusoidal variation with the same frequency as the traveling wave. If you looked at another point along the wave, it'd carry out the same sinusoidal variation, but phase shifted.

If the phase at some x1 and x2 is
phi_1 = kx1 - wt, phi_2 = kx2 - wt,
the phase difference is phi_1 - phi_2 is k(x1 - x2)
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top