Does the line lie in the plane?

AI Thread Summary
To determine if the line through point P(1, 2, 3) with direction vector d = (1, 2, -3) lies in the plane defined by the equation 2x + y - z = 3, the dot product of the plane's normal vector (2, 1, -3) and the direction vector must equal zero. The calculated dot product does not equal zero, indicating that the line does not lie in the plane. Additionally, point P does not satisfy the plane equation, confirming it is not on the plane. Thus, both the line and point are confirmed to be outside the plane. The conclusion is that the line does not lie in the plane.
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Homework Statement


Does the line through the point P(1, 2, 3) with direction vector d = (1, 2, -3) lie in the plane 2x+y-z=3?

Homework Equations

The Attempt at a Solution


From the 2x+y-z i can get the vector (2, 1, -3) and the direction vector, their dot product does not equal zero. So, no it does lie on the plane. Just wondering if my intuition is correct.
 
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Yes because, as you might have added, ##\langle 2,1,3\rangle## is perpendicular to the plane. Or you might have noticed that P isn't in the plane in the first place.
 
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