Double Integral Surface Area of Spherical Ball

Philosophaie
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Homework Statement



Double Integral Surface Area of Spherical Ball radius

Homework Equations



##\int_S d\vec{S} = 4*\pi*a^2##

The Attempt at a Solution



##\int\int_0^a f(r,?) dr d? = 4*\pi*a^2##
 
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Philosophaie said:

Homework Statement



Double Integral Surface Area of Spherical Ball radius

Homework Equations



##\int_S d\vec{S} = 4*\pi*a^2##

The Attempt at a Solution



##\int\int_0^a f(r,?) dr d? = 4*\pi*a^2##


What is the dS element in spherical coordinates?
 
##dS = r^2*sin\phi*d\theta*d\phi##

I can take it from here!
 
Good. Remember the only two variables are ##\theta## and ##\phi##. The radius is constant.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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