- #1

cse63146

- 452

- 0

## Homework Statement

[tex]\int^{0}_{-3}\int^{\sqrt{9 - x^2}}_{- \sqrt{9 - x^2}} \sqrt{1 + x^2 + y^2} dy dx[/tex]

## Homework Equations

x = rcos(theta)

y = rsin(theta)

## The Attempt at a Solution

By making [tex]\sqrt{9 - x^2} = y[/tex] then changing it to polar coordinates, I got r to be +/-3

but I'm not sure how to find what theta is bounded by. From what I read, since its [tex]\sqrt{1 + x^2 + y^2}[/tex] it's in the first quadrant. Not sure what to do now.