- #1
cse63146
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Homework Statement
[tex]\int^{0}_{-3}\int^{\sqrt{9 - x^2}}_{- \sqrt{9 - x^2}} \sqrt{1 + x^2 + y^2} dy dx[/tex]
Homework Equations
x = rcos(theta)
y = rsin(theta)
The Attempt at a Solution
By making [tex]\sqrt{9 - x^2} = y[/tex] then changing it to polar coordinates, I got r to be +/-3
but I'm not sure how to find what theta is bounded by. From what I read, since its [tex]\sqrt{1 + x^2 + y^2}[/tex] it's in the first quadrant. Not sure what to do now.