Double integrals, trying to be sure I am not doing something wrong

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1. evaluate the following:

\int^{1}_{0}\int^{1}_{0}xyex+y dydx

The Attempt at a Solution



OK, so this should be pretty simple. But for some reason I am having trouble integrating the yex+y bit with respect to y. If I do it by parts I end up with iterations like this:

\int^{1}_{0}xyex+y - \int^{}_{}ex+yxdy dx

And integrating again I got

\int^{1}_{0}xyex+y - ex+yx |^{1}_{0} dx plugging in the relevant values I got

\int^{1}_{0}xex+1-xex+1 - xex + xexdx

which with the latter terms cancelling gets you \int^{1}_{0}xex+1-xex+1 dxAnd the whole thing should go to zero.

OK, did I do this whole bit correctly? I want to make sure that I am not doing something stupid. If I did it right, wonderful. (I know this might sound kind of silly to post a problem that I think I did correctly, but it never hurts to have another pair of eyes)
 
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I don't have time to run through your work right now, but surely something is wrong since your integrand is positive. You must have a positive result. Why don't you try writing ##e^{x+y} = e^xe^y## and separate the integrals. Really easy then.
 
Emspak said:
1. evaluate the following:

\int^{1}_{0}\int^{1}_{0}xyex+y dydx


The Attempt at a Solution



OK, so this should be pretty simple. But for some reason I am having trouble integrating the yex+y bit with respect to y. If I do it by parts I end up with iterations like this:

\int^{1}_{0}xyex+y - \int^{}_{}ex+yxdy dx

And integrating again I got

\int^{1}_{0}xyex+y - ex+yx |^{1}_{0} dx

You're correct up to here. After here is where your solution diverges from correct solution.

P.S. It may be helpful in the future to check computationally:
 
Thanks, I did it again and I realized I forgot the y component. D'OH!
 
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