Double-slit Interference for Photons and Electrons

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In a double-slit interference experiment, the kinetic energy of electrons must match the interference pattern of photons to maintain the same spacing between maxima. The relationship involves equating the de Broglie wavelength of electrons with the wavelength of photons, expressed as λ(p) = hc/Eγ and λ(e) = h/(2mEe)^(1/2). To find the kinetic energy of the electrons (Ee), one can solve the equation derived from these wavelengths. The discussion highlights confusion over the calculations and the principles governing the behavior of photons versus electrons in this context. Understanding the de Broglie wavelength is crucial for solving the problem effectively.
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Homework Statement


A double-slit interference experiment is performed with photons of energy Eγ. The same pair of slits is then used for an experiment with electrons. What is the kinetic energy of the electrons if the interference pattern is the same as for the photons (that is, the spacing between maxima is the same)? Express your answer in terms of Eγ, me (electron mass), and c (speed of light).

Homework Equations



The Attempt at a Solution


I really hate to do this, but I have absolutely no idea what it is asking me here or how to do it.

How does using photons and electrons change the outcome? I am unsure how to calculate the kinetic energy...do I modify the dsinΘ=mλ equation somehow?

I am really lost here!
 
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Energy of photon = hc/lambda. hence lambda(p) = hc/Ey
For electrons lambda(e) = h/mv = h/(2mEe)^1/2
Equate lambda(p) and lambda(e) and solve for Ee
 
For electrons, that's the de Broglie wavelength, correct? I had just happened across that in my notes, but didn't get so far as to change momentum to (2mEe)1/2

Thank you for responding at such a late hour >_< I was not expecting such a quick reply!
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

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