Doubling the frequency of a quantum harmonic oscillator

AI Thread Summary
A particle in the ground state of a harmonic oscillator experiences a sudden doubling of its classical frequency from w to w' = 2w, without an immediate change in the wavefunction. The energy measurement after this change is questioned, specifically whether it can still yield the original energy value of h'w/2. The relevant equations include the Hamiltonian H and the energy levels En for the harmonic oscillator. The discussion reveals uncertainty about the probability of measuring the original energy, with initial instincts suggesting it might be zero. Clarification on the implications of the frequency change on the wavefunction and energy states is sought.
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Homework Statement



A particle is in the ground state of a harmonic oscillator with classical frequency w. Suddenly the classical frequency doubles, w -> w' = 2w without initially changing the wavefunction. Instantaneously afterwards, what is the probability that a measurement of energy would still return the value h'w/2? (where h' denotes h-bar).

Homework Equations



Earlier in the question, I had to show that H = (a'*a + 1/2)h'w where a' and a are the creating and annihilation operators, respectively. Also, En = (n+1/2)h'w for a harmonic oscillator.

The Attempt at a Solution



I'm honestly not at all sure how to approach this; my instinct would be to say that it has a probability of 0, but that seems unlikely.
 
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I know that the wavefunction is psi_n = (1/sqrt(2^n * n!))*(a'^n)*psi_0, so a measurement of energy after the frequency has changed would be En' = (n+1/2)h'w' = (n+1/2)(2)h'w. Any help would be greatly appreciated; thank you!
 
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