Doubling Water Pump Rate: Increase Motor Power?

AI Thread Summary
To double the water pump rate from the same pipe, the power of the motor must be increased by a factor of eight, based on the relationship between flow rate and power. This is derived from the principle that power is proportional to the cube of the flow rate in a pump system. The discussion emphasizes the importance of providing relevant equations and attempted solutions when seeking help. Participants are encouraged to engage with the problem rather than simply request answers. Understanding the underlying physics is crucial for effective problem-solving in this context.
Himal kharel
Messages
79
Reaction score
0

Homework Statement


A pump motor is used to pump water at a certain rate from a given pipe. to increase the rate
of pumping of water 2 times from same pipe by how much times power of motor must be increased?


Homework Equations





The Attempt at a Solution


 
Physics news on Phys.org
Please follow the rules of this forum and fill in the template when you seek help with homework. Show us the relevant equations and tell us what you tried and what you think about the problem. We just don't give answers away.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top