- #1
JosephLee
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1. a 1400 kg car with a cross section of 1.8m wide and 1.46m high slides across a frictionless surface at 19 m/s.
The question is how long does it take (in seconds) to get to 13 m/s?
the 2nd part is how long it does it take to get to 10 m/s?
2. D = .5(A)v^2 where A is the area of cross section
and basic mechanics equation V = Vo + at
3. The real problem lies in the fact that drag changes over the change in velocity. I tried solving for it initially by plugging in different velocities for the drag equation but it doesn't come out right.
So far, there is a drag force going backwards and the momentum of the car going forwards. I'm so frustrated because i believe that I am missing something very simple to solve this.
The question is how long does it take (in seconds) to get to 13 m/s?
the 2nd part is how long it does it take to get to 10 m/s?
2. D = .5(A)v^2 where A is the area of cross section
and basic mechanics equation V = Vo + at
3. The real problem lies in the fact that drag changes over the change in velocity. I tried solving for it initially by plugging in different velocities for the drag equation but it doesn't come out right.
So far, there is a drag force going backwards and the momentum of the car going forwards. I'm so frustrated because i believe that I am missing something very simple to solve this.
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