Drawing a shear force diagram with loads working at an angle

AI Thread Summary
To incorporate an angled load into a shear force diagram, it is essential to split the force into its vertical and horizontal components. Only the vertical component contributes to the shear force, while the horizontal component does not affect it. The process involves calculating the vertical component using trigonometric functions based on the angle of the load. After determining the vertical forces, they can be plotted on the shear force diagram, ensuring that the total shear force sums to zero at the supports. Understanding this method is crucial for accurately representing forces in structural analysis.
dreamliner
Messages
16
Reaction score
0
I was wondering how you incorporate an angled load into a shear force diagram? So far I've only been working with vertical loads and I've looked through my entire book without finding an example with loads at an angle, so I'm not sure what to do here. I know I have to end up at 0 so I see I can't just continue on 25 downwards...

Figure with measurements attached.
 

Attachments

  • Shear force.jpg
    Shear force.jpg
    4.3 KB · Views: 1,228
Physics news on Phys.org
You would need to split the force at an angle into vertical and horizontal components. Only the vertical will produce a shear force.
 
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanged mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top