 #1
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Homework Statement
I just have a problem with (A) & (B)
The attempt at a solution
Analysing all possible products;
(A) can give 1pentene (minor) + 2pentene (major). But you also have the EZ diastereomers of 2pentene. So that's total 3 possible products.
(B) will give only the diastereomers E & Z 2pentene. So 2 possible products
Hence, (A)→(s) & (B)→(r)
But they've given (A)→(r) & (B)→(s)
How can it be?
I just have a problem with (A) & (B)
The attempt at a solution
Analysing all possible products;
(A) can give 1pentene (minor) + 2pentene (major). But you also have the EZ diastereomers of 2pentene. So that's total 3 possible products.
(B) will give only the diastereomers E & Z 2pentene. So 2 possible products
Hence, (A)→(s) & (B)→(r)
But they've given (A)→(r) & (B)→(s)
How can it be?
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