E2 elimination using alc.KOH

  • #1
236
21
Homework Statement
I just have a problem with (A) & (B)
IMG_20180719_173721.JPG

The attempt at a solution
Analysing all possible products;
(A) can give 1-pentene (minor) + 2-pentene (major). But you also have the E-Z diastereomers of 2-pentene. So that's total 3 possible products.
(B) will give only the diastereomers E & Z 2-pentene. So 2 possible products
Hence, (A)→(s) & (B)→(r)
But they've given (A)→(r) & (B)→(s)
How can it be?
 

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Answers and Replies

  • #2
mjc123
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Books are not infallible.
 
  • #3
236
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Are you sure? No hitch? We aren't missing anything?
 
  • #4
mjc123
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Nope. S, R, Q, P.
 

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