Easy Electric Potentional Problem

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The electric potential difference between the ground and a cloud in a thunderstorm is 1.5 billion volts (1.5E9 V). To calculate the change in electric potential energy of an electron, the formula U = qV is used, where q is the charge of the electron (1.6e-19 Coulombs). The initial calculation yielded 2.4e-19 GeV, but the units needed conversion to eV or GeV. The correct approach is to divide by the charge of the electron, leading to a final result of 1.5 GeV. Understanding unit conversions is crucial in electromagnetism calculations.
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Homework Statement



The electric potential difference between the ground and a cloud in a particular thunderstorm is 1.5E9 V. What is the magnitude of the change in the electric potential energy of an electron that moves between the ground and the cloud?

_____ GeV

Homework Equations



U\q=V

The Attempt at a Solution



This should be simple.

U=qV
U=(1.6e-19)(1.5 GV)
U=2.4e-19 GeV

Why is this not right?
 
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Anyone? Still can't figure it out.
 
NO one at all?
 
exitwound said:

The Attempt at a Solution



This should be simple.

U=qV
U=(1.6e-19)(1.5 GV)
U=2.4e-19 GeV

Why is this not right?

What are the units on the 1.6e-19? Include the units in the calculation.
 
Coulombs. I'm not following.
 
Correct.

That would make the units in your answer Coulombs*V, and not eV. You'll have to convert to eV (or GeV).
 
So, ... what, I divide by 1.6x10^-19?

U=2.4e-19 / 1.6e-19 = 1.5 GeV

There are too many stupid units in electromagnetism! This is driving me crazy.
 
exitwound said:
So, ... what, I divide by 1.6x10^-19?
Yes. (Or don't multiply by 1.6x10^-19 in the first place.)

U=2.4e-19 / 1.6e-19 = 1.5 GeV
Yes, you got it. :smile:

There are too many stupid units in electromagnetism! This is driving me crazy.
You get used to it after awhile.

By the way, if you use elementary charge units instead of Coulombs here, it's simpler:

An electron has -1.00 elementary charges or -1.00 e of charge, so

U = q V
= (1.00 e) (1.5e9 V)
= ___ eV
= ___ GeV​
 
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