Effective Resistance of a circuit

AI Thread Summary
The discussion revolves around calculating the effective resistance of a circuit, with the user detailing their approach from both right to left and left to right. They correctly calculated the effective resistance as 22.5Ω using both methods, but questioned why treating certain resistors as series connections led to an incorrect answer. The clarification provided indicates that the resistors in question are not in series, validating the right-to-left approach as the correct method. The user is encouraged to adhere to the proper circuit configuration to avoid errors in future calculations. Understanding the arrangement of resistors is crucial for accurate resistance calculations.
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Homework Statement



Revered members,
I need to find the effective resistance of this circuit which i have given in attachment.
circuit.

Homework Equations


The Attempt at a Solution


Now let me explain how i carried out.
I proceeded from right to left
1) R s = 12 + 6 = 18Ω
2) Rp = R1 R2/R1 + R2 which is (18 x 6)/24 = 4.5Ω
3) R = R1 + R2 = 18 + 4.5 = 22.5Ω
I have given the above steps in my second attachment
Now, for the same problem when i proceed from left to right
1) I took 18Ω and 6Ω as parallel i got 4.5 Ω and then this 4.5 is in series with
12 Ω and 6Ω so 4.5 + 12 + 6 = 22.5Ω
I have given the above steps in my third attachment
Now my question is why should not i take 18 Ω and 6Ω as series connection and proceed, because when i take those 18 Ω and 6Ω as described in my last attachment in the following reply,
i get wrong answer. Where do i go wrong?

Homework Statement


Homework Equations


The Attempt at a Solution

 

Attachments

  • prob.png
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  • IMG_0001.jpg
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  • IMG.jpg
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continuing my previous query, this is my last attachment. Is this not a series circuit? But when i take this as series and proceed from left to right, i get wrong answer.
 

Attachments

  • picture.jpg
    picture.jpg
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why should not i take 18 Ω and 6Ω as series connection and proceed?
Because, in the first image, they are not in series. You were correct in proceeding from right to left (2nd image).
 
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