Efficiently Solving a Simple Pulley Question with Mass and Force Calculations

  • Thread starter Thread starter I_LuV_FiZiX
  • Start date Start date
AI Thread Summary
To raise herself slowly at constant speed using the bucket-pulley system, the window washer must consider the forces acting on the bucket. The total mass of the person and bucket is 66.3 kg, leading to a gravitational force of approximately 650 N. The key to solving the problem lies in understanding the tension in the rope, which is equal to the weight when there is no acceleration. The pulley arrangement involves two parallel strings, with the washer pulling down on one side to lift herself and the bucket. Properly analyzing the tension will lead to the correct force needed for her upward movement.
I_LuV_FiZiX
Messages
27
Reaction score
0

Homework Statement


A window washer pulls herself upward using the bucket-pulley apparatus shown in figure below.


Homework Equations


With what force must she pull downward to raise herself slowly at constant speed? The mass of person plus bucket is 66.3 kg.


The Attempt at a Solution


f=ma
f=66.3 x 9.8
f=650N
wrong?
 
Physics news on Phys.org
I_LuV_FiZiX said:

Homework Statement


A window washer pulls herself upward using the bucket-pulley apparatus shown in figure below.


Homework Equations


With what force must she pull downward to raise herself slowly at constant speed? The mass of person plus bucket is 66.3 kg.


The Attempt at a Solution


f=ma
f=66.3 x 9.8
f=650N
wrong?

Hi I_LuV_FiZiX! :smile:

(You haven't told us what the pulley arrangement is. :rolleyes:)

Hint: in these questions, always ask yourself what the tension in the rope is. :wink:
 
the pulley arrangement is two strings parallel to each other with a pulley at the top, she is in the bucket attached to the string on the left, and she is pulling down on the pulley on the right in order to bring her and the bucket up...thanks for considering my question :smile:
 
I_LuV_FiZiX said:
the pulley arrangement is two strings parallel to each other with a pulley at the top, she is in the bucket attached to the string on the left, and she is pulling down on the pulley on the right in order to bring her and the bucket up

ok … then consider the forces on the bucket … what is the tension in the rope if there is no acceleration? :smile:
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top