Elastic and inelastic collisions

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Homework Help Overview

The discussion revolves around the nature of elastic and inelastic collisions, particularly focusing on particle collisions involving low-energy and high-energy protons. Participants explore the conditions under which collisions are classified as elastic or inelastic, referencing specific scenarios and equations related to kinetic energy and momentum conservation.

Discussion Character

  • Conceptual clarification, Assumption checking, Exploratory

Approaches and Questions Raised

  • Participants discuss the differences in collision outcomes based on energy levels and the implications of relativistic effects on mass. Questions are raised about the criteria for determining whether a collision is elastic or inelastic, particularly in the context of subatomic particles.

Discussion Status

The conversation includes various interpretations of collision types, with some participants suggesting that the classification depends on whether the colliding particles remain unchanged. Others express confusion about specific equations used in the analysis of collisions, indicating a need for further clarification.

Contextual Notes

There is mention of conflicting information regarding the nature of subatomic collisions, with some sources claiming they are generally elastic while others provide examples of inelastic collisions. Additionally, the discussion touches on the implications of relativistic speeds on mass and collision outcomes.

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Homework Statement


A low-energy particle collides elastically with a stationary particle of the same mass. The angle between the subsequent paths of both particles are 90 degrees.
But when a high-energy proton collides with a stationary proton, the angle between the two paths is not 90 degrees. Why is it so?

Homework Equations


½ mu2 = ½ mv2 + ½ ms2

The Attempt at a Solution


I answered that it's because the collision was not elastic so the above equation couldn't apply. But the answer is that because the proton is moving near speed of light so it's mass is greater than rest mass. So is this collision between the two protons still an elastic one? How to know whether a collision is an elastic or an inelastic one by its nature? I saw on some websites they say subatomic collisions are elastic but from another past paper it says the scattering between electrons and hydrogen nuclei is an inelastic collision...
 
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mystreet123 said:

Homework Statement


A low-energy particle collides elastically with a stationary particle of the same mass. The angle between the subsequent paths of both particles are 90 degrees.
But when a high-energy proton collides with a stationary proton, the angle between the two paths is not 90 degrees. Why is it so?

Homework Equations


½ mu2 = ½ mv2 + ½ ms2

The Attempt at a Solution


I answered that it's because the collision was not elastic so the above equation couldn't apply. But the answer is that because the proton is moving near speed of light so it's mass is greater than rest mass. So is this collision between the two protons still an elastic one? How to know whether a collision is an elastic or an inelastic one by its nature? I saw on some websites they say subatomic collisions are elastic but from another past paper it says the scattering between electrons and hydrogen nuclei is an inelastic collision...
The collision is elastic if the colliding parties remain the same. If two protons collide, both of them remain the same protons. If an electron collides with a proton, you can get a neutron and a neutrino , for example; or you can get a hydrogen atom - these are inelastic collisions.
 
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ehild said:
The collision is elastic if the colliding parties remain the same. If two protons collide, both of them remain the same protons. If an electron collides with a proton, you can get a neutron and a neutrino , for example; or you can get a hydrogen atom - these are inelastic collisions.
Thank you so much!
 
I never understood why the equation was ½ mu2 = ½ mv2 + ½ ms2 in the first place. I understand the mu and mv portion, but I don't quite understand the ms part of the equation. What is it derived from?
 
Disputationem said:
I never understood why the equation was ½ mu2 = ½ mv2 + ½ ms2 in the first place. I understand the mu and mv portion, but I don't quite understand the ms part of the equation. What is it derived from?
Note that you are responding to a five year old thread to ask a peripherally related question.

My response moved to https://www.physicsforums.com/threa...sions-between-particles.1006366/#post-6531530
 
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