Elastic Collision shuffleboard problem

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SUMMARY

The discussion addresses the elastic collision of two shuffleboard pucks of equal mass, focusing on the conservation of momentum and kinetic energy principles. The user derived equations for the x and y components of the velocities post-collision: 0.95 = Vx1*cos50 + Vx2*cos40 and 0 = Vy1*sin50 - Vy2*sin40. The key takeaway is the necessity to apply both conservation laws separately for each component to solve for the final velocities of the pucks.

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Homework Statement



A moving shuffleboard puck has a glancing collision with a stationary puck of the same mass. If friction is negligible, what are the speeds of the pucks after the collision?
http://img179.imageshack.us/img179/277/phyqp2.jpg

The Attempt at a Solution


I ended up with this:
0.95 = Vx1*cos50 + Vx2*cos40
and
0= Vy1*sin50 - Vy2*sin40

--
I know that both momentum and energy are conserved in elastic collision but I got no idea how to actually apply the concept. I think I'm looking too much into it and missing something simple. Thanks
 
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You can apply it in a similar way to the way you used conservation of momentum. What is the equation for conservation of kinetic energy? Split this up into x and y components ike you did with the momentum.
 

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