Electric and Gravitational Forces & Fields

AI Thread Summary
The discussion revolves around calculating electric and gravitational forces on a proton in Earth's atmosphere, where the electric field is 150 N/C downward and the gravitational field is 9.80 N/kg downward. For the electric force, the correct approach involves using the charge of the proton, which is 1.60 x 10-19 C, leading to the formula Fe = q * E, resulting in Fe = 2.40 x 10-17 N. The gravitational force is calculated correctly using Fg = mg, yielding Fg = 1.64 x 10-26 N. The confusion stemmed from misapplying the charge and the gravitational field in the electric force calculation. Clarifying the charge of the proton resolved the initial frustration with the calculations.
811 trolley
Messages
2
Reaction score
0
I'm getting pretty frustrated with this equation, and I'm not sure what I'm really doing. I've gone to the teacher for help, but as soon as I left school and came home, I've drawn a blank about what he told me..

"At a point in Earth's atmosphere, the electric field is 150 N/C downward and the gravitational field is 9.80 N/kg downward.

a) Determine the electric force on a proton (p+) placed at this point.

b) Determine the gravitational force on the proton at this point. The proton has a mass of 1.67 x 10-27 kg."


For a), I'm pretty sure you use the formula:
E = Fe/q, and then manipulate it to find Fe, right?

I tried doing this:
Fe = q * E
Fe = 9.80 N/kg * 150 N/C

I get Fe = 1470 N, when in the back of the textbook it says I should get 2.40 x 10-17 N
So I'm not getting the answer that it says in the textbook. I was wondering if I did something wrong with 'q', because isn't that the charge, which should be in coulombs? Am I supposed to use the gravitational field and the mass of the proton to find the charge?

I also tried this:
Fe = (1.67 x 10-27 * 9.80 N/kg) * 150 N/C
and I got Fe = 2.50 x 10-24 N
Still the wrong answer.
Maybe I'm entering it wrong into my calculator?

As for b), I was told to use:
g = Fg/m, then manipulate it to this:
Fg = mg
Fg = 1.67 x 10-27 * 9.80 N/kg

Fg = 1.64 x 10-26 N
which is right, so I don't really know why I typed this all down! Haha
 
Last edited:
Physics news on Phys.org
Fe = q * E
Fe = 9.80 N/kg * 150 N/C
q here is charge. What is the charge of a proton? Don't worry about "g" for this part of the question. It doesn't have anything to do with the electric force.
 
hage567 said:
q here is charge. What is the charge of a proton? Don't worry about "g" for this part of the question. It doesn't have anything to do with the electric force.

Oh, yeah. So instead of 1.67 x 10-27 N/kg, I use 1.60 x 10-19 C.

Fe = 1.60 x 10-19 C * 150 N/C
Fe = 2.40 x 10-17 N

Thanks! I get so frustrated, I seem to just miss one little thing that screws up the answer! I can't believe I did that..
 
Yeah, it happens!
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top