Electric charge in parallel plate capacitor with 2 parallel dielectrics

AI Thread Summary
In a parallel plate capacitor with two parallel dielectrics, the total electric charge is indeed the sum of the charges in each dielectric, expressed as qtotal = q1 + q2 = σ1*A/2 + σ2*A/2. The discussion raises questions about the neutrality of dielectrics and clarifies the configuration of the dielectrics—whether they are side by side or stacked. It emphasizes the need to identify commonalities between the two halves to derive relevant equations. Participants are encouraged to complete their attempts at solutions while adhering to forum guidelines. Understanding the arrangement and properties of the dielectrics is crucial for solving the problem accurately.
AndrejN96
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Homework Statement


My question is: If we have a parallel plate capacitor with 2 parallel dielectrics both taking A/2 of the complete surface, is the total electric charge equal to sum of the electrical charges in the first dielectric and the second dielectric, i.e is qtotal=q1+q2=σ1*A/2+σ2*A/2?

Homework Equations


Ctotal=C1+C2

The Attempt at a Solution

 
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Aren't dielectrics supposed to be neutral ?
Try to find something the two halves have in common.
Re problem statement: what are parallel dielectrics in this context? Are there two capacitors side by side or is there a stack of two dielectris between two capacitor plates ?

Re equations: Try to find something the two halves have in common and find equations that involve it
And please fill in the attempt at solution. We aren't allowed to assist otherwise. See PF guidelines
 

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