Electric field across a parallel plate capacitor

  • Thread starter johnj7
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  • #1
johnj7
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Hello,

If I had a potential source (V) , a resistor R, and a parallel plate capacitor,

would the Electric field across the capacitor become

E = (V - IR)/L

L = distance between capacitor

or would the electric field simply become E = V/L

??

thank you!!
 

Answers and Replies

  • #2
Delphi51
Homework Helper
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How is the circuit set up? Your E = (V - IR)/L would be correct for a purely series circuit. But the current would be zero (or quickly become zero as the capacitor charges) so your second formula is then correct.
 
  • #3
LowlyPion
Homework Helper
3,115
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Hello,

If I had a potential source (V) , a resistor R, and a parallel plate capacitor,

would the Electric field across the capacitor become

E = (V - IR)/L

L = distance between capacitor

or would the electric field simply become E = V/L

That very much depends on whether the resistor is in series or in || with the capacitor doesn't it?
 
  • #4
johnj7
27
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Ah ic, oh okay I understand now.

so if in series,
clearly initially it is

E = (V-IR) /L
but after the capcitor is fully charged then E = V/L

however if in parallel from the start then

E = V/L, always

would this be correct?
 
  • #5
Delphi51
Homework Helper
3,407
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If the V, R and C are all in parallel then they all have the same potential V.
 

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