• Support PF! Buy your school textbooks, materials and every day products via PF Here!

Electric field across a parallel plate capacitor

  • Thread starter johnj7
  • Start date
27
0
Hello,

If I had a potential source (V) , a resistor R, and a parallel plate capacitor,

would the Electric field across the capacitor become

E = (V - IR)/L

L = distance between capacitor

or would the electric field simply become E = V/L

??

thank you!!
 

Delphi51

Homework Helper
3,407
10
How is the circuit set up? Your E = (V - IR)/L would be correct for a purely series circuit. But the current would be zero (or quickly become zero as the capacitor charges) so your second formula is then correct.
 

LowlyPion

Homework Helper
3,079
4
Hello,

If I had a potential source (V) , a resistor R, and a parallel plate capacitor,

would the Electric field across the capacitor become

E = (V - IR)/L

L = distance between capacitor

or would the electric field simply become E = V/L
That very much depends on whether the resistor is in series or in || with the capacitor doesn't it?
 
27
0
Ah ic, oh okay I understand now.

so if in series,
clearly initially it is

E = (V-IR) /L
but after the capcitor is fully charged then E = V/L

however if in parallel from the start then

E = V/L, always

would this be correct?
 

Delphi51

Homework Helper
3,407
10
If the V, R and C are all in parallel then they all have the same potential V.
 

Related Threads for: Electric field across a parallel plate capacitor

Replies
3
Views
5K
Replies
1
Views
1K
Replies
3
Views
1K
Replies
4
Views
3K

Physics Forums Values

We Value Quality
• Topics based on mainstream science
• Proper English grammar and spelling
We Value Civility
• Positive and compassionate attitudes
• Patience while debating
We Value Productivity
• Disciplined to remain on-topic
• Recognition of own weaknesses
• Solo and co-op problem solving
Top