Electric field at perpendicular distance R due to a Solenoid

AI Thread Summary
The discussion focuses on calculating the electric field at a perpendicular distance from a solenoid with a time-varying current described by I=I_0sin(wt). Using Faraday's law, the relationship between the electric field and magnetic flux is established, leading to the equation 2πrE = -1/c d/dt(Magnetic flux). The magnetic flux is then expressed in terms of the solenoid's current, allowing for the calculation of the electric field E. The participant initially struggled with the integration and application of Faraday's law but ultimately clarified the steps needed to solve for E. The thread concludes with a successful resolution of the problem.
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Homework Statement


A solenoid as viewed from the left has a current carrying wire wrapping around it counter clockwise. The current travels from left to right. The current varies as:

I=I_0sin(wt)

According to Faraday's law, this will result in electric field. From symmetry, the electric field on a concentric circle is constant, and the electric field lines are concentric. Apply Faraday's law on a concentric circle of radius r to find an expression for the electric field at a perpendicular distance r from the solenoid.


Homework Equations


I believe I am supposed to be using Faraday's Law:

Integral of E.dS = -d/dt(Magnetic flux)
(Sorry, still trying to figure out how to use latex.)

The Attempt at a Solution



Well, we just finished doing Lenz's Rule, and I was good up until he brought electric field into it. Do I have to replace E in terms of I? I guess I just really don't get it, and I can't find it anywhere in his online notes or on the web. Help!
 
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EDIT: I figured it out. I needed to use the equation Integral of E.dS = -1/c d/dt(Magnetic flux)where c is the speed of light. The integral was over a circular path, so it ended up being 2πrE = -1/c d/dt(Magnetic flux). From there, I replaced the magnetic flux with μ0I_{0}sin(wt) and solved for E.
 
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