Electric field between two charged rods

AI Thread Summary
The discussion focuses on calculating the electric field strengths between two uniformly charged glass rods placed 4.0 cm apart. The user attempts to compute the electric field at 2.0 cm from the left rod using the formula for electric field strength but initially overlooks the direction of the fields from each rod. It is clarified that the electric fields from the two rods are in opposite directions, affecting the final calculation. The user references a specific physics textbook for context and suggests reviewing course materials for better understanding. Overall, the importance of considering the direction of electric fields in calculations is emphasized.
aliaze1
Messages
173
Reaction score
1

Homework Statement



Two 10-cm-long thin glass rods uniformly charged to are placed side by side, 4.0 cm apart. What are the electric field strengths at distances 1.0 cm, 2.0 cm, and 3.0 cm to the right of the rod on the left, along the line connecting the midpoints of the two rods?

Homework Equations



[1/(4??0)] * {|Q| / [r* (r2+(0.5L)2)0.5]}
the power "0.5" is the square root; √

The Attempt at a Solution



Calculating the charge @ 2cm seemed the easiest, so here is what I did:

L=0.1m
r=0.02m
Q=1*10-8
1/(4??0) = 9*109

plugging these numbers in, I get 83562.90218, and since there are two rods, and this is equidistant from both, I added Erod#1 + Erod#2, which is the same as doubling the value, giving 167125.8044; incorrect
 
Physics news on Phys.org
The two fields due to each rod are in opposite directions.
 
learningphysics said:
The two fields due to each rod are in opposite directions.

so their signs are opposite...thanks!
 
This question is from section 27.3, Question 9 from the book "Physics for scientists and engineers second edition. A strategic approach" by Randall D. Knight, which is probably the most standard undergraduate physics text available and extremely good, and it even has answers for all the odd numbered questions.

I suggest reading your course material.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Back
Top