Electric Field & Capcitor Problem HELP

AI Thread Summary
The discussion centers on solving a physics problem involving an electron moving through a parallel plate capacitor. The key parameters include the electron's initial speed of 4.00 x 10^6 m/s, the capacitor's length of 2.00 cm, and a plate separation of 0.150 cm. Participants clarify that the force on the electron can be calculated using F=ma=qE, where q is the charge of the electron, which is -1.6 x 10^(-19) coulombs. The confusion primarily revolves around determining the electric field's magnitude. The conversation highlights the importance of referencing known constants in physics problems.
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Electric Field & Capcitor Problem HELP!

Homework Statement



An electron enters the lower left side of a parallel plate capacitor & exits at the upper right side making an upward curve. The initial speed of the electron is 4.00 x 10^6 m/s. The capacitor is 2.00 cm long, and its plates are separated by 0.150 cm. Assume that the electric field between the plates is uniform everywhere and find its magnitude.

The Attempt at a Solution



So I understand that F=ma=qE. I also understand that I can use kinematics to find the acceleration and I can also use the mass of an electron to figure out the force. However, how do I find q? I'm so confused!:confused: Please help! Thanks!
 
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q is the charge of the electron. You don't compute it, you look it up. -1.6*10^(-19) coulombs.
 
Thank you so much! That's great...duh.
 

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