Electric Field due to a Point Charge

hpayandah · Jun 12, 2013

Homework Statement

Looking at the picture I have attached the problem is very straight forward. In the denominator of the equations I have posted the teacher uses 2[itex]\Pi[/itex] but the book uses 4[itex]\Pi[/itex]. Can someone please explain to me why is that.

Homework Equations

Book's equation:

Equation 3.9: E = q/(4πε₀) · (r₁ − r₂)/|r₁ − r₂|³ = q/(4πε₀R²) · a_R, the electric field of a point charge in vector form.

Teacher's Soln:

Handwritten derivation for Problem 3.13 with line charges P+ = 1 μC/m and P- = -1 μC/m, computing the field from position vectors R1 and R2 and a diagram showing the two lines at y = -3 and y = 3 with field vectors E1 and E2 meeting at x = 4.

The Attempt at a Solution

Please refer to attached pictures.

hpayandah · Jun 12, 2013

I was finally able to solve my problem. By the way from the two y points there is infinite line of charge in the z-axis. Here is my answer:

Handwritten derivation of the electric field of an infinite line charge using Gauss's law, followed by superposition of two line charges at points on the y-axis, ending with a final vector expression for the field.

Electric Field due to a Point Charge

Homework Statement

Homework Equations

The Attempt at a Solution

Discussion

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