Electric field in a solid cylinder with an offset hole

AI Thread Summary
The discussion focuses on calculating the electric field within a cylindrical cavity of radius R/2 in a solid cylinder of radius R with uniform charge density. Participants explore the application of Gauss's Law and the principle of superposition to find the electric field in the cavity. Initial assumptions about the electric field being zero are corrected, with emphasis on the need to consider the contributions from both the solid cylinder and the offset cavity. The correct approach involves calculating the electric fields produced by both the full cylinder and the cavity, leading to a resultant field direction determined by the geometry of the setup. Ultimately, the conversation highlights the importance of careful integration of fields in cylindrical coordinates to arrive at the correct solution.
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[SOLVED] Electric field in a solid cylinder with an offset hole

Homework Statement


question5.jpg

its teenie, but it says: Superposition: an infinite cylinder of radius R and uniform charge density (row) contains a cylindrical cavity of radius R/2 as shown. Find the electric field in the cavity.



Homework Equations



Gauss's Law I guess.



The Attempt at a Solution


My first thought was 'zero. duh'...but that's not exactly superposition. I know there has to be something about the whole cylinder minus the hole...but I'm not sure how to go about integrating with a common origin or...I've just gotten myself very confused. HELP!
 
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Here's a hint: A negative charge can cancel a positive charge. :wink:
 
Let E_1 the wanted electric field, E_2 the electric field produced by the cylinder R/2 alone and E_3 the electric field produced by the cylinder R. Then

E_1+E_2=E_3\Rightarrow E_1=E_3-E_2


The electric fields E_2, E_3 are easily obtained by Gauss law.
 
thank you thank you
however...easily obtained by gauss's law...easily...I'm having a very blonde afternoon...I can't seem to pick a reference frame that works for both E1 and E2. And do I treat E2 as a cylindrical shell with uniform charge distribution? Or as nothing...not that it really matters...its still zero right?
 
Come up with two solid uniform cylinders of charge which add up to give you the needed charge configuration.
 
Hey there, I take it you're in Phys 231/239 as well?
 
wow...lol.
Yup 239.
Have you finished it?
 
I'm done the assignment except for this question. I too was having some trouble combining the two fields (awkward using two separate cylindrical coordinate systems). I think I've figured it out now though.

I'm technically in 231, but it's just 239 renamed for us purple folk.
 


Doc Al said:
Come up with two solid uniform cylinders of charge which add up to give you the needed charge configuration.
Hi, I'm having trouble with the same problem. The center of the cavity is at a distance A from the center of the big cylinder. My calculations of superpositioning the two fields yields an electric field within the cavity equal to zero. Is this correct?
 
  • #10


irish_coffee said:
My calculations of superpositioning the two fields yields an electric field within the cavity equal to zero. Is this correct?
No, that's not correct. Show how you came to that conclusion.
 
  • #11


I know, I discovered it was nonsense. I now have calculated the vector product of the vector field produced by the big solid cylinder with charge density rho and the vector field produced by the small cylinder with charge density minus rho. Because this adds up to the situation we have here (a big cylinder with a cavity with density of zero). The direction of the resulting vector field in an arbitrary point P within the cavity is in the direction of the vector connecting the center of the big cylinder and the center of the cavity.
 
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