Electric Field MCQ Homework Help

AI Thread Summary
The discussion revolves around understanding electric fields and their properties in relation to homework questions. Participants agree that options a) and c) are correct, while option b) is debated based on the application of Gauss's law and the behavior of electric field lines. There is confusion regarding the convergence of electric field lines and whether this implies a zero charge enclosed within a sphere. Clarifications are provided about the electric field pointing towards the origin and the implications of charge density on the divergence of the electric field. The conversation emphasizes the need for careful computation and interpretation of results in the context of electric fields.
Vibhor
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Homework Statement



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Homework Equations


The Attempt at a Solution



I believe a) and c) are correct options . Regarding option b) if I find charge q as function of radius , then option b) also seems correct . But if I think in terms of electric field lines then I am not sure about option b) .

Since electric field lines converge at the origin , then suppose if I take a sphere of radius 1 unit centered at say (4,4,4) ,then shouldn't the number of lines entering the sphere be same as that leaving the sphere . Applying Gauss's law the charge enclosed should be zero .

Is convergence of electric field same as convergence of electric field lines ?

Please help me in removing the doubt .

Many Thanks
 

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Vibhor said:

Homework Statement



?temp_hash=f5cb82b3929718ca4405f41b542c0fd0.png


Homework Equations


The Attempt at a Solution



I believe a) and c) are correct options . Regarding option b) if I find charge q as function of radius , then option b) also seems correct . But if I think in terms of electric field lines then I am not sure about option b) .

Since electric field lines converge at the origin , then suppose if I take a sphere of radius 1 unit centered at say (4,4,4) ,then shouldn't the number of lines entering the sphere be same as that leaving the sphere . Applying Gauss's law the charge enclosed should be zero .

Is convergence of electric field same as convergence of electric field lines ?

Please help me in removing the doubt .

Many Thanks

I would say the electric field points to the origin instead of converging towards it. The electric field is a function of the position, it can converge at a value when approaching the origin. This field converges to zero at the origin.
Can you write the electric field ##E(\vec r)## as function of the position vector ?
You are right, options a) and c) are correct. That also means c) is wrong.
b) is easy to answer if you use the differential form of Gauss theorem. ##Div \vec E = \rho(\vec r) /ε_0## where ρ is the charge density at a given position ##\vec r##.
It is not sure that the net flux is zero in case of a closed surface not centered around the origin.
 
Neither (c) nor (d) look right to me.
4πr2ε(100r) = Q ≠ 3e-9 and also ≠ 3e-13?
 
rude man said:
Neither (c) nor (d) look right to me.
4πr2ε(100r) = Q ≠ 3e-9 and also ≠ 3e-13?
Why? C is correct to 3 digits.
 
ehild said:
Why? C is correct to 3 digits.
Right. Quite a coincidence given r = 3 (cm.). But I interpreted the answer 3e-13 as absolute. Shoulkd have done the computation.
 
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