Electric field of infinite nonconducting sheets

AI Thread Summary
The discussion revolves around calculating the electric field due to two infinite nonconducting sheets of charge with a uniform surface charge density of +3.80 µC/m². The user believes their calculations for the electric field in regions outside the sheets (x < -2.85 m and x > 2.85 m) are correct, yielding values of -4.3 x 10^5 N/C and +4.3 x 10^5 N/C, respectively. However, they are receiving feedback from a website indicating an error. A suggestion is made that the user may need to include the unit vector in their answer. Clarifying the inclusion of unit vectors could resolve the discrepancy in the user's calculations.
nizsu
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Hi, I am doing homework for my physics class and I think I am doing it right but the website keep saying I am wrong. Can anybody tell me where I am wrong? Thank you

Two infinite nonconducting sheets of charge are parallel to each other, with sheet A in the x = -2.85 plane and sheet B in the x = +2.85 m plane. Find the electric field in the region x < -2.85 m, in the region x > +2.85 m, and between the sheets for the following situations.
(a) when each sheet has a uniform surface charge density equal to +3.80 µC/m2

When x< -2.85, E= -4pikσ = -4.3*10^5
When x > 2.85. E = 4pikσ = 4.3*10^5
 
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nizsu said:
Hi, I am doing homework for my physics class and I think I am doing it right but the website keep saying I am wrong. Can anybody tell me where I am wrong? Thank you

Two infinite nonconducting sheets of charge are parallel to each other, with sheet A in the x = -2.85 plane and sheet B in the x = +2.85 m plane. Find the electric field in the region x < -2.85 m, in the region x > +2.85 m, and between the sheets for the following situations.
(a) when each sheet has a uniform surface charge density equal to +3.80 µC/m2

When x< -2.85, E= -4pikσ = -4.3*10^5
When x > 2.85. E = 4pikσ = 4.3*10^5
That's what I get too.

Maybe you're expected to include the unit vector, \hat{i}\,.
 
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