Electric field of ring causing oscillation

AI Thread Summary
A ring with a radius of 18 cm and a uniform positive charge of 5 µC causes a particle with a negative charge of -5 µC to oscillate about its center with an angular frequency of 12 rad/s. The problem asks for the new angular frequency if the ring's radius is doubled to 36 cm while keeping other parameters constant. The electric field of the ring can be utilized to derive the force acting on the particle, which is analogous to a mass-spring system. By applying the approximation that the distance from the charge to the center of the ring is much smaller than the radius, the force can be calculated. The discussion emphasizes the need to find the new angular frequency using the relationship between force, mass, and angular frequency.
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Homework Statement


A ring of radius 18 cm that lies in the yz plane
carries positive charge of 5 µC uniformly distributed over its length. A particle of mass m
that carries a charge of −5 µC executes small
oscillations about the center of the ring on its
axis with an angular frequency of 12 rad/s.
Find the angular frequency of oscillation of
the mass if the radius of the ring is doubled to
36 cm and all other parameters above remain
unchanged.


Homework Equations


{Hint: it is useful to draw an analogy between this problem and a mass-spring system.
For the latter, the force on the mass is given by
F = ma = −kx and produces 1d simple harmonic oscillation with an angular frequency
of ω = (k/m)^(1/2)}

Electric field of a uniformly charged ring: (1/(4*pi*epsilon))*q*z/(R^2+z^2)^(3/2)

The Attempt at a Solution

Well I took the electric field of the ring and multiplied it by the charge of the particle mass to get the force. I also took the angular frequency and squared it to get k/m, but after that I'm just stuck. I really just wish I knew what to do. Thanks for your help. I really appreciate it.
 
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ponyhunter said:

Homework Statement


A ring of radius 18 cm that lies in the yz plane
carries positive charge of 5 µC uniformly distributed over its length. A particle of mass m
that carries a charge of −5 µC executes small
oscillations about the center of the ring on its
axis with an angular frequency of 12 rad/s.
Find the angular frequency of oscillation of
the mass if the radius of the ring is doubled to
36 cm and all other parameters above remain
unchanged.


Homework Equations


{Hint: it is useful to draw an analogy between this problem and a mass-spring system.
For the latter, the force on the mass is given by
F = ma = −kx and produces 1d simple harmonic oscillation with an angular frequency
of ω = (k/m)^(1/2)}

Electric field of a uniformly charged ring: (1/(4*pi*epsilon))*q*z/(R^2+z^2)^(3/2)

The Attempt at a Solution

Well I took the electric field of the ring and multiplied it by the charge of the particle mass to get the force. I also took the angular frequency and squared it to get k/m, but after that I'm just stuck. I really just wish I knew what to do. Thanks for your help. I really appreciate it.

The question says that charge performs oscillations near the centre of the ring. This means that z (assuming it is the distance of charge from centre of ring) is much smaller than the radius of ring (R) i.e z<<R. Use this approximation and find the force on the charge.
 
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