Electric Field problem Is my math wrong or am I doing something else wrong?

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Homework Help Overview

The discussion revolves around calculating the electric field at a point midway between a -7.0 µC and a +6.0 µC charge that are 5.0 cm apart. Participants are examining the contributions of each charge to the electric field and the implications of their signs based on the direction of the field produced by each charge.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formula for electric field contributions and the importance of considering the direction of each charge's field. Questions arise regarding the proper assignment of signs to these contributions based on their respective directions.

Discussion Status

Some participants have expressed confusion about the direction of the electric fields and how to correctly apply the signs in their calculations. Guidance has been offered to clarify the reasoning behind the direction of the electric fields produced by positive and negative charges. There is acknowledgment of differing interpretations regarding the placement of the charges and their effects on the resultant electric field.

Contextual Notes

Participants note that the problem does not specify which charge is on the left or right, leading to potential ambiguity in the analysis of the electric field directions.

Bensky
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Electric Field problem :( Is my math wrong or am I doing something else wrong?

Homework Statement


What are the magnitude and direction of the electric field at a point midway between a -7.0 µC and a +6.0 µC charge 5.0 cm apart? Assume no other charges are nearby.

Homework Equations



E = KQ_1/r^2 + KQ_2/r^2

The Attempt at a Solution



Q_1 = -7X10^-6 C
Q_2 = 6X10^-6 C
K = 9X10^9
r = 0.025m

E = KQ_1/r^2 + KQ_2/r^2
E = (K)(-7X10^-6)/(.025^2) + (K)(6X10^-6)/(.025^2)
E = -100800000 + 86400000
E = -14400000 N/C or -1.44 X 10^7 N/C (incorrect)

Direction: toward the negative charge (correct)
 
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Bensky said:
E = KQ_1/r^2 + KQ_2/r^2
E = (K)(-7X10^-6)/(.025^2) + (K)(6X10^-6)/(.025^2)
Careful! You must think through each contribution to the total field in order to give it the proper sign. (You can't just plug into the formula.)

Let's say the negative charge is on the left and the positive charge is on the right. Using what you know about the direction of the field from a point charge, which direction is each field contribution at the point in question? Once you've figured out the direction, then you can give it the proper sign. (For example: To the left = negative; to the right = positive.)
 
Doc Al said:
Careful! You must think through each contribution to the total field in order to give it the proper sign. (You can't just plug into the formula.)

Let's say the negative charge is on the left and the positive charge is on the right. Using what you know about the direction of the field from a point charge, which direction is each field contribution at the point in question? Once you've figured out the direction, then you can give it the proper sign. (For example: To the left = negative; to the right = positive.)

I am slapping myself now. Of course Doc Al is right. The two E-fields at the center point in the same direction. I erased my post since it was completely wrong.
 
Doc Al said:
Careful! You must think through each contribution to the total field in order to give it the proper sign. (You can't just plug into the formula.)

Let's say the negative charge is on the left and the positive charge is on the right. Using what you know about the direction of the field from a point charge, which direction is each field contribution at the point in question? Once you've figured out the direction, then you can give it the proper sign. (For example: To the left = negative; to the right = positive.)

Thanks, I got the answer right, but I'm not sure why I got it right. I ended up making both of them positive and adding them, but from the problem it doesn't seem like the charges would go in the same direction. Why is this so?
 
Bensky said:
Thanks, I got the answer right, but I'm not sure why I got it right. I ended up making both of them positive and adding them, but from the problem it doesn't seem like the charges would go in the same direction. Why is this so?

You must ask yourself in what direction the electric field produced by each charge points.

The question is not quite clear because they don't say which charge is on the left and which charge is on the right. Let's pretend the positive charge is on the left and the negative charge is to its right.

Then ask yourself: in what direction is the E field produced by the positive charge at a point midway between the two charges?
In what direction is the E field produced by the negative charge at that point?
Answer those questions and it should clear up why you had to add them up.



Now, to make sure you understand, repeat with this time the positive charge on the right and the negative charge on the left. You will find the the E field points in a different direction but the magnitude of the E field will be the same as before
 
Last edited:
Bensky said:
Thanks, I got the answer right, but I'm not sure why I got it right. I ended up making both of them positive and adding them, but from the problem it doesn't seem like the charges would go in the same direction. Why is this so?
Looks like kdv gave you a good answer (while I was busy with another thread). Study it and answer his questions step by step.

This fact about charges, which you should know, is key: The field from a positive charge points away from the charge; the field from a negative charge points toward the charge.
 
Thank you to both of you, I understand now.
 

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