What is the speed of a proton after moving in a uniform electric field?

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A uniform electric field of 3.0x10^3 N/C accelerates a proton initially moving at 2.3x10^4 m/s over a distance of 0.003 m. To find the final speed, the force on the proton is calculated using F=qE, where the charge of the proton is 1.6x10^-19 C. The user initially struggled with the negative sign of the charge but clarified that it should be treated as positive for this calculation. After determining the acceleration, the kinematics equations can be applied to find the proton's final speed. The discussion emphasizes the importance of correctly identifying the charge of the proton in calculations.
NeoKrypt
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A uniform electric field has a magnitude of 3.0x10^3 N/C. In a vacuum, a proton begins with a speed of 2.3x10^4 m/s and moves in the direction of this field. Find the speed of the proton after it has moved a distance of .003 m.

I try to work out the problem with the equation F=qE to find the acceleration and plug that into a kinematics equation, but I do not have q. Can anyone help?
 
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You are told it is a proton, so it has a charge equal in magnitude to an electron (with opposite sign). 1.6*10^-19 C, I think. You should look it up in your textbook.
 
ah got it! I actually tried that just before I posted on here except I left the negative sign on the charge. Thanks alot!
 
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