- #1
radiant_june
- 2
- 1
Find the electric field strength at point B between two charges shown below:
Given/Known Values
q1 = 4.0×10-6 C
r1 = 40 cm = 0.4 m (Distance from q1 to point B)
q2 = -1.0×10-6 C
r2 = 30 cm = 0.3 m (Distance from q2 to point B)
k = 9.0×109 Nm2/C2
Equations
E1 = (k⋅q1)/r12
= (9.0×109⋅4.0×10-6)/0.42
= 225000 N/C
E2 = (k⋅q2)/r22
= (9.0×109⋅-1.0×10-6)/0.32
= -100000 N/C
ΔE = EB = E1 - E2
= 225000 - (-100000)
= 325000 N/C
I'm not really sure if this is the correct way of finding the electric field strength of point B. Any help would be appreciated!
Given/Known Values
q1 = 4.0×10-6 C
r1 = 40 cm = 0.4 m (Distance from q1 to point B)
q2 = -1.0×10-6 C
r2 = 30 cm = 0.3 m (Distance from q2 to point B)
k = 9.0×109 Nm2/C2
Equations
Electric Force:
Electric Field:
My thought process was that I could find the electric field strengths of both charges, and then find the difference between them, since point B is between the two charges.FE = (k⋅q1⋅q2)/r2
FE = q⋅E
FE = q⋅E
Electric Field:
E = (k⋅q)/r2
E1 = (k⋅q1)/r12
= (9.0×109⋅4.0×10-6)/0.42
= 225000 N/C
E2 = (k⋅q2)/r22
= (9.0×109⋅-1.0×10-6)/0.32
= -100000 N/C
ΔE = EB = E1 - E2
= 225000 - (-100000)
= 325000 N/C
I'm not really sure if this is the correct way of finding the electric field strength of point B. Any help would be appreciated!